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27 August, 13:46

A soccer ball kicked from the ground with an initial velocity of 32 ft/s is given by the function

h (t) = - 16 + 321. When is the soccer ball moving through the air?

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Answers (1)
  1. 27 August, 13:57
    0
    In words the answer is between t=0 and t=2.

    In interval notation the answer is (0,2)

    In inequality notation the answer is 0
    Big note: You should make sure the function I use what you meant.

    Step-by-step explanation:

    I hope the function is h (t) = -16t^2+32t because that is how I'm going to interpret it.

    So if we can find when the ball is on the ground or has hit the ground (this is when h=0) then we can find when it is in the air which is between those 2 numbers.

    0=-16t^2+32t

    0=-16t (t-2)

    So at t=0 and t=2

    So the ball is in the air between t=0 and t=2

    Interval notation (0,2)

    Inequality notation 0
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