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29 May, 16:16

Angles A and B are complementary angles in a right triange. The value of cos (A) is 12/13. What is the value of Tan (A)

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  1. 29 May, 16:42
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    Using the pythagorean identity, we can find the value of sin (A)

    cos^2 (A) + sin^2 (A) = 1

    (12/13) ^2 + sin^2 (A) = 1

    144/169 + sin^2 (A) = 1

    sin^2 (A) = 1 - 144/169

    sin^2 (A) = 169/169 - 144/169

    sin^2 (A) = (169 - 144) / 169

    sin^2 (A) = 25/169

    sin (A) = sqrt (25/169)

    sin (A) = 5/13

    Which is then used to find tan (A)

    tan (A) = sin (A) / cos (A)

    tan (A) = (5/13) divided by (12/13)

    tan (A) = (5/13) * (13/12)

    tan (A) = (5*13) / (13*12)

    tan (A) = 5/12

    The final answer is 5/12
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