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20 March, 19:07

Find the first five terms of the geometric sequence whose constant ratio is - 5 and whose first term is 6.

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Answers (2)
  1. 20 March, 19:08
    0
    Answer: 6, - 30, 150, - 750 and 3750.

    Step-by-step explanation:

    First term = 6

    Second term = ar = 6 * (-5) = - 30

    Third term = ar^2 = 6 * (-5) (-5) = 150

    Forth term = ar^3 = 6 * (-5) ^3 = - 750

    Fifth term = ar^4 = 6 * (-5) ^4 = 3750
  2. 20 March, 19:32
    0
    Answer: 6,-30,150,-750,3750

    Step-by-step explanation:

    Geometric progression formula is

    An=a1r^ (n-1)

    An = nth term

    A1 = first term

    R = common ratio

    N = nth position

    A1=6

    R=-5

    We already know the first term, looking for 2nd 3rd 4th & 5th

    A2=a1r^ (n-1)

    A2=6 * (-5^ (2-1))

    A2=6 * (-5^1)

    A2=6*-5

    A2 = - 30

    A3=a1r^ (n-1)

    A3=6 * (-5^ (3-1))

    A3=6 * (-5^ (2))

    A3=6 * (25)

    A3 = 150

    A4=a1r^ (n-1)

    A4=6 * (-5^ (4-1))

    A4=6 * (-5^3)

    A4=6*-125

    A4 = - 750

    A5=a1r^ (n-1)

    A5=6 * (-5^ (5-1))

    A5=6 * (-5^ (4))

    A5=6 * (625)

    A5=3750

    The first 5 numbers are

    6,-30,150,-750,3750
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