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4 June, 13:26

Evaluate each expression.

6! =

3!. 21 =

11

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Answers (1)
  1. 4 June, 13:41
    0
    here we work with factorials, so if we have a whole number N, then:

    N! = N * (N-1) * ... * 2*1

    then, for the given expressions we have:

    1) 6! = 6*5*4*3*2*1 = 720.

    2) 3!*21 = (3*2*1) * 21 = 216

    3) and the last expression seems incomplete, i guess this is:

    11! = 11*10*9*8*7*6*5*4*3*2*1 = 39,916,800
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