Which of the following are solutions to the equation sinx cosx = square root 3/4 check all that apply

Important to note: sin2x = 2sinxcosx

Since we know that property, we can divide both sides by 2 to yield: sin2x/2 = sinxcosx

So, sin2x/2 = sqrt (3) / 4

sin2x = 2sqrt (3) / 4 = sqrt (3) / 2

2x = arcsin (sqrt (3) / 2) = 60, 120 in the domain [0, 360]

x = 30, 60