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26 October, 13:50

How do you solve

(x-5) ^2-4 (x-5) - 21=0

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Answers (1)
  1. 26 October, 13:59
    0
    Let's solve your equation step by step.

    (x-5) ^2 - 4 (x - 5) - 21 = 0

    Step 1: Simply both sides of the equation.

    x^2 - 14x + 24=0

    Step 2: Factor left side of the equation.

    (x - 2) (x - 12) = 0

    Step 3: Set factors equal to 0.

    x - 2 = 0 or x - 12 = 0

    x = 2 or x = 12

    Answer:

    x = 2 or x = 12
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