Let 0 be an angle such that cot 0 = - 4/7 and sec 0 >0.

Find the exact values of cos 0 and csc 0.

Question

Damian Delacruz

Mathematics

30 October, 22:23

Let 0 be an angle such that cot 0 = - 4/7 and sec 0 >0.

Find the exact values of cos 0 and csc 0.

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Answers (1)

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Bobo · Answer 1

Cos 0 = 4/sqrt (65)

Cosec 0 = - sqrt (65) / 7

Step-by-step explanation:

Cot 0 = - 4/7

Tan 0 = - 7/4

1 + Tan²0 = sec²0

1 + 49/16 = 65/16 = sec²0

Sec 0 = sqrt (65) / 4

Cos 0 = 1 : sec 0

Cos 0 = 4/sqrt (65) or 4sqrt (65) / 65

Cosec 0 = cot 0 * sec 0

= - 4/7 * sqrt (65) / 4

= - sqrt (65) / 7

Let 0 be an angle such that cot 0 = - 4/7 and sec 0 >0.Find the exact values of cos 0 and csc 0.

Let 0 be an angle such that cot 0 = - 4/7 and sec 0 >0.

Find the exact values of cos 0 and csc 0.