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23 September, 16:01

If y varies inversely as the square of x, and y = 1/8 when x = 1, find y when x = 5.

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  1. 23 September, 16:07
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    Y = k / x² (y varies inversely as the square of x)

    y = 1/8 when x = 1:

    1/8 = k / 1²

    8 k = 1

    k = 1/8

    For x = 5:

    y = 1/8 / 5² = 1/8 : 25 = 1/8 · 1/25 = 1/200

    Answer: A) 1/200
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