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21 September, 17:19

Trigonometry

Trigonometric Equations

csc x cot x + cot x = 0; x [ 0, 2π ]

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Answers (2)
  1. 21 September, 17:25
    0
    x=π/2,3π/2

    Step-by-step explanation:

    cot x (csc x+1) = 0

    either cot x=0

    tanx=∞=tan (π/2)

    x=π/2

    or csc x=-1

    or sin x=-1=-sin (π/2) = sin (π+π/2) = sin (3π/2)

    x=3π/2
  2. 21 September, 17:46
    0
    x = π/2, 3π/2

    Step-by-step explanation:

    cosecxcotx + cotx = 0

    cotx (cosecx + 1) = 0

    cotx = 0

    x = π/2,

    π + π/2 = 3π/2

    cosecx = - 1

    x = 3π/2

    x = π/2, 3π/2
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