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23 April, 16:44

Use the equation and type the ordered-pairs.

y = log₂ x

(1/2,__), (1,__), (2,__), (4,__), (8,__), (16,__) }

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Answers (2)
  1. 23 April, 18:06
    0
    y = log₂ x is: { (1/2, - 1), (1, 0), (2, 1), (4, 2), (8, 3), (16, 4) }
  2. 23 April, 18:27
    0
    Hello!

    To find the y-values of the given ordered pairs, substitute the x-values into the equation, y = log₂ x.

    y = log₂ 1/2, y = - 1

    y = log₂ 1, y = 0

    y = log₂ 2, y = 1

    y = log₂ 4, y = 2

    y = log₂ 8, y = 3

    y = log₂ 16, y = 4

    Therefore, the ordered pairs of y = log₂ x is: { (1/2, - 1), (1, 0), (2, 1), (4, 2), (8, 3), (16, 4) }.
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