The height of an arrow shot upward can be given by the formula s = v0t - 16t2, where v0 is the initial velocity and t is time. How long does it take for the arrow to reach a height of 48 ft if it has an initial velocity of 96 ft/s? Round to the nearest hundredth. The equation that represents the problem is 48 = 96t - 16t2. Solve 16t2 - 96t + 48 = 0.

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28 July, 22:33

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Kyra Mendez · Answer 1

(t - 3) ² = 6

t - 3 = + / - 2.45

t = 5.45s, 0.55s

Answer: The arrow is at a height of 48 ft after approximately 0.55s and 5.45s