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5 October, 16:21

What is the solution set to the equation x^2+6x+3=0

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  1. 5 October, 16:27
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    That is a quadratic equation in which

    a = 1

    b = 6

    c = 3

    The quadratic formula is:

    x = [-b + - sqr root (b^2 - 4*a*c) ] / 2*a

    x = [-6 + - sqr root (36 - 4 * 1 * 3) ] / 2

    x1 = [-6 + sqr root (24) ] / 2

    x2 = [-6 - sqr root (24) ] / 2
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