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28 May, 08:03

What is the solution of the equation e^xe^2x = 4? Round your answer to the nearest hundredth.

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  1. 28 May, 08:10
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    The equation is:

    [e^x] [e^ (2x) ] = 4

    1) Applying property of multiplication of powers wiith same base = >

    e ^ (x + 2x) = 4

    => e ^ (3x) = 4

    2) Applying logarigth properties

    3x = ln (4)

    => x = ln (4) / 3 ≈ 1.38629 / 3 ≈ 0.4621

    Answer: x = ln (4) / 3 ≈ 0.4621
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