What is the smallest of three consecutive positive integers if the product of the smaller two integers is 10 more than 4 times the largest integers?

Question

April Horn

Mathematics

3 September, 01:39

What is the smallest of three consecutive positive integers if the product of the smaller two integers is 10 more than 4 times the largest integers?

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Answers (1)

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Immanuel Cannon · Answer 1

The smallest is 6

Three consecutive integers

X. Smallest 6

X+1. 7

X+2. Largest 8

X (X+1) = 4 (X+2) + 10

X^2+X = 4x+8+10

X^2+X-4x-18=0

X^2-3x-18=0

(X+3) (X-6)

X=-3. X=6

Don't use the negative

Check 6 (7) = 4 (8) + 10

42=42