Which equations have a leading coefficient of 3 and a constant term of - 2? Check all that apply.

0 = 3x2 + 2x - 2

0 = - 2 - 3x2 + 3

0 = - 3x + 3x2 - 2

0 = 3x2 + x + 2

0 = - 1x - 2 + 3x2

Question

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Mathematics

22 August, 05:55

Which equations have a leading coefficient of 3 and a constant term of - 2? Check all that apply.

0 = 3x2 + 2x - 2

0 = - 2 - 3x2 + 3

0 = - 3x + 3x2 - 2

0 = 3x2 + x + 2

0 = - 1x - 2 + 3x2

+4

Answers (1)

Know the Answer?

Josue Schneider · Answer 1

Answers are: choice A, choice C, choice E

Explanation: The leading coefficient is the number that is to the left of the term with the largest exponent, which in this case is 2. The term 3x^2 is the leading term with the coefficient of 3. This is why the leading coefficient is 3 for choice A, choice C, and choice E. Choice B has a leading coefficient of - 3 so we can rule that out. Choice D has a leading coefficient of 3, but the constant term is NOT - 2. Instead the constant term is + 2, so we can rule out choice D as well. The other choices that haven't been eliminated all have 3x^2 somewhere in them, as well as the constant term - 2. The other x term isn't relevant to the restrictions placed in the instructions.

Which equations have a leading coefficient of 3 and a constant term of - 2? Check all that apply.0 = 3x2 + 2x - 20 = - 2 - 3x2 + 30 = - 3x + 3x2 - 20 = 3x2 + x + 20 = - 1x - 2 + 3x2

Which equations have a leading coefficient of 3 and a constant term of - 2? Check all that apply.

0 = 3x2 + 2x - 2

0 = - 2 - 3x2 + 3

0 = - 3x + 3x2 - 2

0 = 3x2 + x + 2

0 = - 1x - 2 + 3x2