Identify the 17th term of a geometric sequence where a1 = 16 and a5 = 150.06. Round the common ratio and 17th term to the nearest hundredth.

1.) a17 ≈ 123,802.31

2.) a17 ≈ 30,707.05

3. a17 ≈ 19,684.01

4.) a17 ≈ 216,654.05

Question

Hadley Brown

Mathematics

8 November, 13:58

Identify the 17th term of a geometric sequence where a1 = 16 and a5 = 150.06. Round the common ratio and 17th term to the nearest hundredth.

1.) a17 ≈ 123,802.31

2.) a17 ≈ 30,707.05

3. a17 ≈ 19,684.01

4.) a17 ≈ 216,654.05

+2

Answers (1)

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Markus Petersen · Answer 1

The geometric sequence formula is expressed as an = a1 * r^ (n-1) where n is an integer. In this case, upon substitution, 150.06 = 16 * r^ (4). extracting r, r is equal to 1.75. Hence the 17th term from the formula is equal to 123802.32.

Identify the 17th term of a geometric sequence where a1 = 16 and a5 = 150.06. Round the common ratio and 17th term to the nearest hundredth.1.) a17 ≈ 123,802.312.) a17 ≈ 30,707.053. a17 ≈ 19,684.014.) a17 ≈ 216,654.05

Identify the 17th term of a geometric sequence where a1 = 16 and a5 = 150.06. Round the common ratio and 17th term to the nearest hundredth.

1.) a17 ≈ 123,802.31

2.) a17 ≈ 30,707.05

3. a17 ≈ 19,684.01

4.) a17 ≈ 216,654.05