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9 December, 23:14

What is the value of the discriminant in the equation shown below?

x^2+3x-6=0

... ?

+4
Answers (2)
  1. 9 December, 23:21
    0
    Discriminant = b^2 - 4ac

    a = 1

    b = 3

    c = - 6

    3^2 - 4 (1x-6)

    9 - (4 x - 6)

    9 - - 24 = 33

    Therefore it has 2 real roots
  2. 9 December, 23:37
    0
    Given:ax^2+bx+c=0The discriminant is:b^2-4 (a) (c) so it would be 33x^2-4 (1) (6)

    3^2 - 4 (1) (-6)

    [a] x^2 [+b] x [+c] = 0[1] x^2 [+3] x [-6] = 09 - 4 (1) (-6) = 9 - (-24)

    =33
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