A rocket is launched from the top of a 100-foot cliff with an initial velocity of 34 feet per second. The height of the rocket t seconds after launch is given by the equation h=-16t2+34t+100. How high will the rocket be after 1 second?

Question

Natalia Wood

Mathematics

19 March, 06:10

A rocket is launched from the top of a 100-foot cliff with an initial velocity of 34 feet per second. The height of the rocket t seconds after launch is given by the equation h=-16t2+34t+100. How high will the rocket be after 1 second?

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Answers (1)

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Eliza Roberson · Answer 1

118 feet

Step-by-step explanation:

h = - 16t² + 34t + 100

In order to find the height of the rocket after 1 second, we substitute t=1 in the above equation

h = - 16 (1) ² + 34 (1) + 100

h=-16 + 34 + 100

h=118 feet

Thus, the rocket will be 118 feet high after 1 second