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15 June, 23:23

What are the zero (s) of the function f (x) 4x^2-36x/x-9

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  1. 15 June, 23:50
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    4x^2-36x/x-9

    = 4x (x-9) / (x-9)

    if 4x = 0, ⇒ x = 0

    x-9 ≠ 0

    zero of function is 0.
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