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TanA+tanB=sin (A+B) / cosAcosB

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  1. 14 May, 09:34
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    Do you need to prove that it is equal?

    If so:

    SinA/cosA + sinB/cosB = (sinAcosB + sinBcosA) / cosAcosB

    (SinAcosB + sinBcosA) / cosAcosB = (SinAcosB + sinBcosA) / cosAcosB
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