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Bennett Mcintosh
Mathematics
14 May, 09:31
TanA+tanB=sin (A+B) / cosAcosB
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Janiyah Serrano
14 May, 09:34
0
Do you need to prove that it is equal?
If so:
SinA/cosA + sinB/cosB = (sinAcosB + sinBcosA) / cosAcosB
(SinAcosB + sinBcosA) / cosAcosB = (SinAcosB + sinBcosA) / cosAcosB
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