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31 May, 21:48

Find the illegal values of b in the fraction 2b2+3b-10 / b2-2b-8

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  1. 31 May, 21:59
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    -2 and 4

    Step-by-step explanation:

    When you look for values that make an expression "illegal" the first step is to look for 3 things.

    1) a variable in a denominator

    - we have b, a variable, in the denominator of this expression

    - values in the denominator cannot be 0

    2) variables under even roots

    - variables under even roots are a restriction because even roots are undefined when there are negative values under them

    - there are no roots in this case so we dont have to worry about that

    3) the literal letters: "log" in the expression

    - there's no "log" in the expression so we dont have to worry about that

    -moving on-

    We have a variable in the denominator, b.

    The expression is a quadratic:

    b^2 - 2b - 8

    You have to find values that make this quadratic 0.

    So you can make an equation setting the quadratics equal to 0.

    b^2 - 2b - 8 = 0

    Solve for b

    Factor:

    (b - 4) (b + 2) = 0

    Because of zero product property we can say:

    b = - 2, b = 4.

    If these values are plugged into your expression, it will be "illegal," or "undefined,"
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