Use the quadratic formula to solve 5x=6x^2-3, what are the values of x?

5x = 6x^2 - 3

6x^2 - 5x - 3

a = 6

b = - 5

c = - 3

x = [-b + - sq root (b^2 - 4ac) ] / 2a

x = [--5 + - sq root (25 - (4*6*-3) ] / 12

x = [5 + - sq root (25 + 72) ] / 12

x = [5 + sq root (97) ] / 12

x = 5 + - 9.84886] / 12

x1 = 1.237405

x2 = - 0.404072