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Tyrese Bradford
Mathematics
2 October, 03:15
Factor: p^2 + 12p + 11.
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Daisy
2 October, 03:37
0
Simplifying
p2 + - 12p + 11 = 0
Reorder the terms:
11 + - 12p + p2 = 0
Solving
11 + - 12p + p2 = 0
Solving for variable 'p'.
Factor a trinomial.
(1 + - 1p) (11 + - 1p) = 0
Subproblem 1
Set the factor ' (1 + - 1p) ' equal to zero and attempt to solve:
Simplifying
1 + - 1p = 0
Solving
1 + - 1p = 0
Move all terms containing p to the left, all other terms to the right.
Add '-1' to each side of the equation.
1 + - 1 + - 1p = 0 + - 1
Combine like terms: 1 + - 1 = 0
0 + - 1p = 0 + - 1
-1p = 0 + - 1
Combine like terms: 0 + - 1 = - 1
-1p = - 1
Divide each side by '-1'.
p = 1
Simplifying
p = 1
Subproblem 2
Set the factor ' (11 + - 1p) ' equal to zero and attempt to solve:
Simplifying
11 + - 1p = 0
Solving
11 + - 1p = 0
Move all terms containing p to the left, all other terms to the right.
Add '-11' to each side of the equation.
11 + - 11 + - 1p = 0 + - 11
Combine like terms: 11 + - 11 = 0
0 + - 1p = 0 + - 11
-1p = 0 + - 11
Combine like terms: 0 + - 11 = - 11
-1p = - 11
Divide each side by '-1'.
p = 11
Simplifying
p = 11
Solution
p = {1, 11}
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