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Cot^2x-csc^2x=-1 for all values of x true or falsse

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  1. 23 May, 00:43
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    Our basis for this equality is the pythagorean theorems of trigonometry. There are three equations for the pythagorean theorems. These are:

    sin²x + cos²x = 1

    1 + tan²x = sec² x

    1 + cot² x = csc² x

    These are all derived from circle geometry on the cartesian plane. Now, the useful trigonometric property to be used is the third one. Rearranging this, we come up with

    cot²x - csc²x = - 1

    This coincided with the given equation. Therefore, this is true. This is because it is already established from the pythagorean theorems.
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