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31 August, 14:28

What are the excluded values of x for x+4 / - 3^2+12x+36

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  1. 31 August, 14:50
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    X+4 / - 3x^2 + 12x + 36

    = x + 4 / - 3 (x^2 - 4x - 12)

    = x - 4 / - 3 (x - 6) (x + 2)

    the excluded values make the denominator = 0

    so they are 6 and - 2 Answer
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