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28 August, 19:22

What is the slope of a line that is perpendicular to the line whose equation is y=4x+1?

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Answers (2)
  1. 28 August, 19:25
    0
    y - 4 x = 1

    Step-by-step explanation:

    y = 4 x + 1

    Using the slope-intercept form, the slope is 4.

    m = 4

    The equation of a perpendicular line to y = 4 x + 1 must have a slope that is the negative reciprocal of the original slope.

    m perpendicular = - 1/4
  2. 28 August, 19:35
    0
    Step-by-step explanation:

    The equation of a straight line can be represented in the slope-intercept form, y = mx + c

    Where c = y intercept

    Slope, m = change in value of y on the vertical axis / change in value of x on the horizontal axis

    From the information given,

    comparing the equation given,

    y=4x+1 with the slope intercept equation, y = mx + c

    Slope, m = 4

    When two slopes are perpendicular, their product is - 1

    Let the slope of the perpendicular line to the one given by the above equation be m1. Therefore,

    m * m1 = - 1

    4 m1 = - 1

    m1 = - 1/4

    Inputting m1 = 4 into the slope intercept equation, it becomes

    y = - 1/4*x + c

    y = - x/4 + c
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