There is 1 red gumdrop and 4 green gumdrops in a small jar. Also, 2 pieces of butterscotch candy and 3 pieces of cinnamon

candy are in another jar. If Craig draws one piece of candy from each jar without looking, what's the probability that he will

get a red gumdrop and a piece of butterscotch candy?

Question

Kira Escobar

Mathematics

29 March, 13:15

There is 1 red gumdrop and 4 green gumdrops in a small jar. Also, 2 pieces of butterscotch candy and 3 pieces of cinnamon

candy are in another jar. If Craig draws one piece of candy from each jar without looking, what's the probability that he will

get a red gumdrop and a piece of butterscotch candy?

+5

Answers (1)

Know the Answer?

Kennedi · Answer 1

The probability that he will get a red gumdrop and a piece of butterscotch candy is 2/25

Step-by-step explanation:

The path to find the answer is to find the probability of both things happening and then multiply them. First, there is 1 red gumdrop and 4 green gumdrops in a jar. There are 5 gumdrops total so the probability of choosing a red one is 1/5. Next, there are 2 pieces of butterscotch candy and 3 pieces of cinnamon candy in another jar. There are 5 pieces of candy total so the probability of choosing a piece of butterscotch candy is 2/5. Finally multiply the two probabilities: 1/5 * 2/5 = 2/25.

There is 1 red gumdrop and 4 green gumdrops in a small jar. Also, 2 pieces of butterscotch candy and 3 pieces of cinnamoncandy are in another jar. If Craig draws one piece of candy from each jar without looking, what's the probability that he willget a red gumdrop and a piece of butterscotch candy?