We want to build a box whose base is square, has no top and will enclose 100 m^3. determine the dimensions of the box that will minimize the amount of material needed to construct the box.

Question

Kaylin Reilly

Mathematics

11 November, 10:02

We want to build a box whose base is square, has no top and will enclose 100 m^3. determine the dimensions of the box that will minimize the amount of material needed to construct the box.

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Rosemary Ross · Answer 1

Let the height of the box be h and the length of a side of the base be s.

Then there are four sides of area hs and one bottom of area s^2.

The volume of this box is then V = (s^2) (h) = 100 m^3. We want to minimize the surface area. The surface area is A = 4sh+s^2.

We can solve the first equation for h and substitute the result into the second equation, to derive a function s alone. If V=hs^2, then h=V/s^2.

Substituting this into A = sh+s^2, A=s (V/s^2) + s^2.

We must minimize this function. First, simplify it to V/s + s^2. Then differentiate it with respect to s:

dA/ds = - V/s^2+2s.

Set this = to 0 and solve for s: 2s=V/s^2. Mult. both sides by s^2:

2s^3=V. Then s^3 = V/2, and s = cube root of V/2.

The dimensions required for minimum surface area are (cube root of V/2) ^2 (area of the base) times h, where h is the height and is equal to V/s^2, or V/[cube root of V/2]^2.