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25 May, 01:39

Which is the solution for log (3x - 1) + log 2 = log 4 + log (x + 2) ?

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Answers (2)
  1. 25 May, 01:47
    0
    x=5

    Step-by-step explanation:

    log (3x-1) + log2=log4+log (x+2)

    log (2 (3x-1)) = log (4 (x+2))

    Cancel log on both sides

    2 (3x-1) = 4 (x+2)

    Open brackets

    6x-2=4x+8

    Collect like terms

    6x-4x=8+2

    2x=10

    Divide both sides by 2

    2x/2=10/2

    x=5
  2. 25 May, 01:56
    0
    Answer:x=1

    Step-by-step explanation:

    log (3x-1) + log2=log4+log (x+2)

    log (2 (3x-1)) = log (4 (x+2))

    Cancel log on both sides

    2 (3x-1) = 4 (x+2)

    Open brackets

    6x-2=4x+8

    Collect like terms

    6x-4x=8+2

    10x=10

    Divide both sides by 10

    10x/10=10/10

    x=1
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