Which is the solution for log (3x - 1) + log 2 = log 4 + log (x + 2) ?

Question

Jayla Bryant

Mathematics

25 May, 01:39

Which is the solution for log (3x - 1) + log 2 = log 4 + log (x + 2) ?

+3

Answers (2)

Know the Answer?

Alyvia Hubbard · Answer 1

x=5

Step-by-step explanation:

log (3x-1) + log2=log4+log (x+2)

log (2 (3x-1)) = log (4 (x+2))

Cancel log on both sides

2 (3x-1) = 4 (x+2)

Open brackets

6x-2=4x+8

Collect like terms

6x-4x=8+2

2x=10

Divide both sides by 2

2x/2=10/2

x=5

Alissa Li · Answer 2

Answer:x=1

Step-by-step explanation:

log (3x-1) + log2=log4+log (x+2)

log (2 (3x-1)) = log (4 (x+2))

Cancel log on both sides

2 (3x-1) = 4 (x+2)

Open brackets

6x-2=4x+8

Collect like terms

6x-4x=8+2

10x=10

Divide both sides by 10

10x/10=10/10

x=1