Which equation, when graphed, has x-intercepts at (2, 0) and (4, 0) and a y-intercept of (0, - 16) ?

Assuming you want quadratic

when x=0, y=-16

y=ax^2+bx+c

-16=0+c

-16=c

when x=2, y=0

0=a (2) ^2+2b-16

0=4a+2b-16

16=4a+2b

8=2a+b

when x=4, y=0

0=a (4) ^2+4b-16

0=16a+4b-16

16=16a+4b

4=4a+b

we has 2 equations

8=2a+b

4=4a+b

multiply first by - 1 and add to 2nd

-8=-2a-b

4=4a+b +

-4=2a+0b

-4=2a

-2=a

sub back

4=4a+b

4=4 (-2) + b

4=-8+b

12=b

y=ax^2+bx+c

y=-2x²+12x-16