At noon joice drove to the lake at 30 mi. per hour, but she made a long walk back at 4 mi. per hour. how long did she walk ifshe was gone for 17 hours?

Distance = 30 mph * time

distance = 4 mph * time

distance = 30 mph * t

distance = 4 mph * (17-t)

Since distance is equal then

30 mph * t = 4 mph * (17-t)

30t = - 4t + 68

34t = 68

t = 2 hours

We see the return trip time is (17 - t) which is 15 hours.

The beginning trip time is 2 hours.

Double Check

Beginning trip = 30 miles * 2 = 60 miles

Return trip = 4 miles * 15 = 60 miles.