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26 January, 09:15

Como se resuelve este problema 3{50-[6•2 (9-5) + 1]}

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  1. 26 January, 09:17
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    3{50-[6*2 (9-5) + 1]}=

    3{50-[6*2 (4) + 1]}=

    3[50 - (6*8+1) ]=

    3[50 - (48+1) ]=

    3 (50-49) =

    3 (1) =

    3
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