A carpenter used 38ft in three pieces to trim a garage door. if the long piece was 2ft longer than twice the length of each shorter piece then how long was each piece?

answer : the long piece was ft long. each shorter piece was ft long.

Question

Lexi

Mathematics

14 April, 14:02

A carpenter used 38ft in three pieces to trim a garage door. if the long piece was 2ft longer than twice the length of each shorter piece then how long was each piece?

answer : the long piece was ft long. each shorter piece was ft long.

+5

Answers (1)

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Raegan Roberson · Answer 1

Let s = shorter piece

Let l = longer piece

l = 2s+2

38=l+2s

Substitute 2s+2 for l

38=2s+2+2s

38=4s+2

36=4s

s=9

l=2s+2

l=2 (9) + 2

l=18+2

l=20

The longer piece was 20 ft. long. Each shorter piece was 9 feet long.

A carpenter used 38ft in three pieces to trim a garage door. if the long piece was 2ft longer than twice the length of each shorter piece then how long was each piece?answer : the long piece was __ ft long. each shorter piece was __ ft long.

A carpenter used 38ft in three pieces to trim a garage door. if the long piece was 2ft longer than twice the length of each shorter piece then how long was each piece?

answer : the long piece was ft long. each shorter piece was ft long.