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2 January, 06:09

What is the inverse of x=4-4y+y^2

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  1. 2 January, 06:33
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    To find invers

    1. solve for y

    2. replace y with xinverse

    so

    x=4-4y+y^2

    reorder right side

    x=y^2-4y+4

    factor right side

    x = (y-2) ^2

    squaer root both sides

    +/-√x=y-2

    add 2 to both sides

    2+/-√x=y

    switch x and y

    2+/-√y=xinverse

    xinverse=2+√y or 2-√y

    subtract 4 from both sides
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