What is the center of the circle with the equation x2 + y2 + 4x-8y+11 = 0?

(-2,4)

Step-by-step explanation:

You do this by completing the square for x and y.

x^2 + 4x + (4/2) ^2 + y^2 - 8x + (-8/2) ^2 = - 11 + 4 + 16

(x + 2) ^2 + (y - 4) ^2 = 9

The center should be (-2,4)