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6 March, 03:48

How do you solve for sinxcos2x+cosxsin2x=0?

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Answers (2)
  1. 6 March, 03:56
    0
    LHS is nothing but (using sin (a+b) = sin a cos b + cos a sin b)

    sin (x+2x) = sin 3x = 0

    so 3x = npi

    or

    x = npi/3
  2. 6 March, 04:13
    0
    The answer is x = n p i divided by 3
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