If a ball is thrown upward at 29.4 meters per second from the top of a building that is 80 meters high, the height of the ball can be modeled by S=4.9t^2 + 29.4t + 80 meters, where t is the number of seconds after the ball is thrown. What is the ball's maximum height (in meters) ?

Question

Tori

Mathematics

1 January, 03:28

If a ball is thrown upward at 29.4 meters per second from the top of a building that is 80 meters high, the height of the ball can be modeled by S=4.9t^2 + 29.4t + 80 meters, where t is the number of seconds after the ball is thrown. What is the ball's maximum height (in meters) ?

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Answers (1)

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Emery · Answer 1

124.1m

Step-by-step explanation:

29.4 per sec > Building 80m

Height = S = 4.9t^2 + 29.4t + 80

Solve for t:

t = 1.24 (approximately)

If t needed coordinates / solve using the quadratic formula:

t = (1.24, - 7.24)

The ball's maximum height is 124.1 meters.