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Christine Morrison
Mathematics
20 September, 03:47
9 (r - s) + 5 (2r - 2s)
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Adrienne Pugh
20 September, 03:49
0
9 (r - s) + 5 (2r - 2s) = 0
perform distributive multiplication
9 (r) + 9 (-s) + 5 (2r) + 5 (-2s) = 0
9r - 9s + 10r - 10s = 0
9r + 10r - 9s - 10s = 0
19r - 19s = 0
19r = 19s
r = 19s/19
r = s
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Amanda Klein
20 September, 04:08
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Ok this isn't as bad as it looks. all you have to do is multiply the terms in the parentheses by the terms outside of them. so it would b 9 x (r-s) + 5 x (2r - 2s).
You would then get (9r-9s) + (10r-10s). Remove the parentheses and combine like terms. 9r + 10r is 19r and - 9s plus - 10s is - 19s. so the answer is 19r - 19s.
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