One root of f (x) = x3+10x2-25x-250=-10. What are all the roots of the function? Use the Remainder Theorem.

x = - 25 or x = 10

x = - 25, x = 1, or x = 10

x = - 10 or x = 5

x = - 10, x = - 5, or x = 5

Question

Esparza

Mathematics

10 July, 05:22

One root of f (x) = x3+10x2-25x-250=-10. What are all the roots of the function? Use the Remainder Theorem.

x = - 25 or x = 10

x = - 25, x = 1, or x = 10

x = - 10 or x = 5

x = - 10, x = - 5, or x = 5

+4

Answers (1)

Know the Answer?

Noel Livingston · Answer 1

If - 10 is a root then x+10 is a factor. As last number = - 250 it could be 5 and - 5 are the other 2 roots

f (5) = 125 + 250 - 125 - 250 = 0 so 5 is one root

f (-5) = - 125 + 250 + 125 - 250 = 0 so - 5 is another root

Answer is D

One root of f (x) = x3+10x2-25x-250=-10. What are all the roots of the function? Use the Remainder Theorem.x = - 25 or x = 10x = - 25, x = 1, or x = 10x = - 10 or x = 5x = - 10, x = - 5, or x = 5

One root of f (x) = x3+10x2-25x-250=-10. What are all the roots of the function? Use the Remainder Theorem.

x = - 25 or x = 10

x = - 25, x = 1, or x = 10

x = - 10 or x = 5

x = - 10, x = - 5, or x = 5