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Roberts
Mathematics
26 March, 14:15
How do you solve 3x+4y=12 and 2x=y-6
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Levi Cardenas
26 March, 14:34
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3x + 4y = 12
2x = y-6 Rewrite this as y = 2x+6
now replace that for y in the first equation
3x + 4 (2x+6) = 12
now do all the calculations:
3x + 8x + 24 = 12
11x + 24 = 12
11x = - 12
x = - 12/11 = - 1 1/11
now substitute - 12/11 for x in the 2nd equation and solve
y = 2x+6
y = 2 (-1 1/11) + 6
y = 42/11 = 3 9/11
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