Find the perimeter of a rectangle is 56 cm. the length of the rectangle is 2 cm more than the width

We call : → l = lenght

We know the perimeter of the

w = width the rectangle : P = 2 (w+l)

P = perimeter

P = 2 (w+l) but l = w+2

56 = 2 (w+w+2)

56 = 2 (2w+2)

56 = 4w + 4

4w = 56 - 4

4w = 52 l = w + 2

w = 52 : 4 l = 13 + 2

w = 13 cm l = 15 cm

P = 56 = 2l + 2w and l=2+w

56 = 2 (2+w) + 2w

56 = 4 + 2w + 2w

52 = 4w

w = 13 cm

l = 13+2

l = 15 cm