In the equation, p and t are constants. What is the value of p? 4x2 - 9 = (px + t) (px - t) A) 2 B) 3 C) 4 D) 9

Question

Ali Ortiz

Mathematics

5 August, 22:36

In the equation, p and t are constants. What is the value of p? 4x2 - 9 = (px + t) (px - t) A) 2 B) 3 C) 4 D) 9

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Answers (1)

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Caden · Answer 1

A) 2

Step-by-step explanation:

4x² - 9 = (px + t) (px - t)

Using formula a² - b² = (a-b) (a+b)

4x² - 9 = (2x) ² - 3² = (2x - 3) (2x+3),

so

(px + t) (px - t) = (2x - 3) (2x + 3).

We can see that p = 2, and t = 3.