Which equation represents the translation of x^2 + y^2=16 by 5 units to the right and 2 units down?

a) (x-2) ^2 + (y+5) ^2=16

b) (x-5) ^2 + (y+2) ^2=16

c) (x+2) ^2 + (y-5) ^2 = 16

d) (x+5) ^2 + (y-2) ^2=16

Question

Zion Johnston

Mathematics

4 June, 09:38

Which equation represents the translation of x^2 + y^2=16 by 5 units to the right and 2 units down?

a) (x-2) ^2 + (y+5) ^2=16

b) (x-5) ^2 + (y+2) ^2=16

c) (x+2) ^2 + (y-5) ^2 = 16

d) (x+5) ^2 + (y-2) ^2=16

+2

Answers (1)

Know the Answer?

Trey Ferguson · Answer 1

The equation, x^2+y^2=16 is an equation of the circle which is centered at (0,0), when the circle is moved 5 units to the right and 2 units down, this implies that the center will be at (5,-2)

the new equation will be:

(x-5) ^2 + (y+2) ^2=16

Answer: B] (x-5) ^2 + (y+2) ^2=16

Which equation represents the translation of x^2 + y^2=16 by 5 units to the right and 2 units down?a) (x-2) ^2 + (y+5) ^2=16b) (x-5) ^2 + (y+2) ^2=16c) (x+2) ^2 + (y-5) ^2 = 16d) (x+5) ^2 + (y-2) ^2=16

Which equation represents the translation of x^2 + y^2=16 by 5 units to the right and 2 units down?

a) (x-2) ^2 + (y+5) ^2=16

b) (x-5) ^2 + (y+2) ^2=16

c) (x+2) ^2 + (y-5) ^2 = 16

d) (x+5) ^2 + (y-2) ^2=16