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19 August, 00:10

What substitution should be used to rewrite 4x^4-21x^2+20=0 as a quadratic function?

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Answers (2)
  1. 19 August, 00:24
    0
    refer the explanation

    Step-by-step explanation:

    this question can be written as

    X^2=y

    so, x^4=y^2

    so it will be 4y^2-21y+20=0
  2. 19 August, 00:32
    0
    see explanation

    Step-by-step explanation:

    Let u = x² (choice of variable is flexible), then

    4u² - 21u + 20 = 0 ← expressed as a quadratic

    This can now be solved for u and converted back into terms of x
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