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1 August, 07:27

An automobile with an initial speed of 4.30 m/s accelerates uniformly at the rate of 3.00 m/s². Find the final speed and the displacement after 5.00 s.

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  1. 1 August, 07:31
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    The final speed and the displacement of the automobile are 19.3 m/s and 59 m respectively

    Step-by-step explanation:

    From Newton's Equation of motion,

    a = v-u/t ... Equation 1

    making v the subject of the equation above,

    v = at + u ... Equation 2

    Where a = acceleration of the automobile, v = final speed, u = initial speed, t = time.

    Given:a = 3.00 m/s², u = 4.3 m/s, t = 5.00 s

    Substituting these values into equation 2,

    v = 3 (5) + 4.3

    v = 15 + 4.3

    v = 19.3 m/s.

    Also using

    v² = u² + 2as

    Making s the subject of the equation,

    s = (v²-u²) / 2a

    Where s = displacement.

    Given: v = 19.3 m/s, u = 4.3 m/s, a = 3 m/s²

    Substituting these values into equation 2

    s = (19.3²-4.3²) / 2*3

    s = (372.49 - 18.49) / 6

    s = 354/6

    s = 59 m

    Thus the final speed and the displacement of the automobile are 19.3 m/s and 59 m respectively
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