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23 December, 05:55

In the system below, use equation (1) with equation (2) to eliminate x. Then use equation (1) with equation (3) to eliminate x. x-y-2z=4 (1) - x+3y-z=8 (2) - 2x-y-4z=-1 (3) What is the new 2 * 2 system?

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  1. 23 December, 06:02
    0
    2y - 3z = 12 - 3y - 8z = 7

    Step-by-step explanation:

    (1) + (2) ⇒ (x - y - 2z) + (-x + 3y - z) = (4) + (8)

    2y - 3z = 12

    __

    2 (1) + (3) ⇒ 2 (x - y - 2z) + (-2x - y - 4z) = 2 (4) + (-1)

    -3y - 8z = 7

    ___

    The reduced system of equations is ...

    2y - 3z = 12 - 3y - 8z = 7
  2. 23 December, 06:25
    0
    2y - 3z = 12.

    -3y - 8z = 7.

    Step-by-step explanation:

    x - y - 2z = 4 (1)

    -x + 3y - z = 8 (2)

    -2x - y - 4z = - 1 (3)

    Adding (1) + (2):

    2y - 3z = 12.

    2 * (1) + (3) gives:

    -3y - 8z = 7.
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