The half-life of a certain radioactive substance is 65 days. There are 3.5 g present initially.

a. Express the amount of substance remaining as a function of time t.

b. When will there be less than 1 g remaining?

r = 3.5 *.5^ (t/65); around 117.5 days

Step-by-step explanation:

r = remaining substance

t = time in days

The half life is 65 day, meaning the. 5 must be put to a power of t/65.

The initial substance was 3.5, which we must substitute in.

After using logarithms to solve our new equation, we are left with t = (about) 117.5 days for there to be less than 1 gram of substance remaining.