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9 August, 19:32

How to factor 4x^2-12=2x

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  1. 9 August, 20:01
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    2 (x - 2) (2x + 3) = 0

    Step-by-step explanation:

    Given

    4x² - 12 = 2x (subtract 2x from both sides)

    4x² - 2x - 12 = 0 ← factor out 2 from each term

    2 (2x² - x - 6) = 0

    To factor the quadratic

    consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x - term

    product = 2 * - 6 = - 12 and sum = - 1

    The factors are - 4 and + 3

    Use these factors to split the x - term

    2x² - 4x + 3x - 6 (factor the first/second and third/fourth terms)

    2x (x - 2) + 3 (x - 2) ← factor out (x - 2) from each term

    (x - 2) (2x + 3), thus

    2x² - x - 6 = (x - 2) (2x + 3) and

    4x² - 2x - 12 = 0

    2 (x - 2) (2x + 3) = 0 ← in factored form
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