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22 July, 23:03

Determine the solutions of the quadratic equation, 2 x squared minus 8 x plus 6 equals 0 using the quadratic formula. x equals the fraction with numerator negative b plus or minus the square root of b squared minus 4 a. c and denominator 2 a.

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  1. 22 July, 23:18
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    1, 3

    Step-by-step explanation:

    2x^2 - 8x + 6 = 0 - ->

    x^2 - 4x + 3 = 0

    (x-1) (x-3) = 0

    x = 1, 3

    OR

    2x^2 - 8x + 6 = 0 - ->

    x^2 - 4x + 3 = 0 - ->

    ( - (-4) + -sqrt ((-4*-4) - 4 (1 * 3))) / 2 - ->

    (4 + -sqrt (4)) / 2 - ->

    (4 + / -2) / 2 - ->

    6/2 or 2/2 - ->

    3, 1
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