An object is thrown downward, with an initial speed of 16 ft/s, from the top of a building 192 ft high. How many seconds later will the object hit the ground? Use the equation

d = vt + 16t2,

where d is the distance in feet, v is the initial speed, and t is the time in seconds.

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26 November, 10:03

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Nico Bates · Answer 1

If the speed is constant and never reaching terminal velocity then the object will hit the ground in 12 seconds.

An object is thrown downward, with an initial speed of 16 ft/s, from the top of a building 192 ft high. How many seconds later will the object hit the ground? Use the equationd = vt + 16t2,where d is the distance in feet, v is the initial speed, and t is the time in seconds.